coding-practice/legacy/3000 areaOfMaxDiagonal/C#/Program.cs

public class Solution
{
    public int AreaOfMaxDiagonal(int[][] dimensions)
    {
        int max = 0;
        int maxArea = 0;

        foreach (var dimension in dimensions)
        {
            var dimensionSqrt = dimension[0] * dimension[0] + dimension[1] * dimension[1];
            var area = dimension[0] * dimension[1];
            if (dimensionSqrt > max)
            {
                max = dimensionSqrt;
                maxArea = area;
            }
            else if (dimensionSqrt == max)
            {
                maxArea = Math.Max(maxArea, area);
            }
        }
        return maxArea;
    }
}

public class Program
{
    public static void Main()
    {
        var Solution = new Solution();

        var dimensions = new int[][] { [6,5],[8,6],[2,10],[8,1],[9,2],[3,5],[3,5]};

        var result = Solution.AreaOfMaxDiagonal(dimensions);
        Console.WriteLine(result);
    }
}